I solved the differential equation d y </mrow> d

2nalfq8

2nalfq8

Answered question

2022-07-12

I solved the differential equation
d y d x = x x 2 + 1
to get the general solution
y = l n | x + 1 | + c 2
Im given the initial condition
y y 2 e x = 0 , y ( 0 ) = 3
but I dont know what to do with it

Answer & Explanation

zlepljalz2

zlepljalz2

Beginner2022-07-13Added 22 answers

y y 2 e x = 0 y ( 0 ) = 3
y d y d x = 2 e x y d y = 2 e x d x
now apply integral
y d y = 2 e x d x 1 2 y ( x ) 2 = 2 e x + c
no apply y(0) to find "c" put x=0
1 2 y ( 0 ) 2 = 2 e 0 + c 1 2 3 2 = 2 + c

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