How would I calculate L^(-1) for the expression (1)/(s+10) L[f(x)]? , where f(x) is arbitary.

Jase Rocha

Jase Rocha

Answered question

2022-09-22

Let L [ f ( x ) ] ( s ) be the Laplace Transformation of a function f(x).
I know L 1 [ 1 s + 10 ] = 1 s ( 10 ) = e 10 x
How would I calculate L 1 for the expression 1 s + 10 L [ f ( x ) ] ?? , where f(x) is arbitary.

Answer & Explanation

baselulaox

baselulaox

Beginner2022-09-23Added 8 answers

L [ f ( x ) s + 10 ]
First you should only have functions of s not x. And you take inverse Laplace Transform not laplace Transform :
L 1 [ F ( s ) s + 10 ]
Use the convolution theorem.
L 1 ( F ( s ) s + 10 ) = 0 t e 10 ( t τ ) f ( τ ) d τ
Where F ( s ) is the Laplace Transform of f(x). F(s) is not given ? Then keep the integral form.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Differential Equations

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?