Bridger Joyce

2023-02-28

Find the sum of interior angles of a polygon with 12 sides in degrees.${1800}^{\circ}\phantom{\rule{0ex}{0ex}}{1200}^{\circ}\phantom{\rule{0ex}{0ex}}{1500}^{\circ}\phantom{\rule{0ex}{0ex}}{1400}^{\circ}$

eirietmmy

Beginner2023-03-01Added 2 answers

sum of a polygon's interior angles with n sides $=(n-2)\times {180}^{\circ}$

∴ Sum of interior angles of a polygon with 12 sides $=(12-2)\times {180}^{\circ}$

$=10({180}^{\circ})$

$={1800}^{\circ}$

∴ Sum of interior angles of a polygon with 12 sides $=(12-2)\times {180}^{\circ}$

$=10({180}^{\circ})$

$={1800}^{\circ}$

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