Jason Farmer

2021-08-17

The probability that a patient recovers from a stomach disease is .8.

Suppose 20 people are known to have contracted this disease.

What is the probability that exactly 14 recover?

Suppose 20 people are known to have contracted this disease.

What is the probability that exactly 14 recover?

jlo2niT

Skilled2021-08-18Added 96 answers

Let Y be the random variable denoting the number of patients that recover from the stomach disease. Y is clearly a binomial random variable as each patient (or trial) is independent and has identical distribution, each patient will either recover or not recover(i.e. has only 2 values).

Here, n=20 and p=0.8.

We need to find P(Y=14). This can be found by using Table Iin Appendix 3 with n=20 and p=0.8.

$P(Y=14)=P(Y\le 14)-P(Y\le 13)=0.196-0.087=0.109$

Result: P(Y=14)=0.109

Here, n=20 and p=0.8.

We need to find P(Y=14). This can be found by using Table Iin Appendix 3 with n=20 and p=0.8.

Result: P(Y=14)=0.109

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