Suppose that X is a binomial random variable with n=200\

Ayaana Buck

Ayaana Buck

Answered question

2021-09-30

Assume that X is an n=200  and  p=0.3 dimensional binomial random variable. Estimate the likelihood that X=80. When using the Binomial distribution technique, compare this outcome. What judgment do you make? 

Answer & Explanation

SkladanH

SkladanH

Skilled2021-10-01Added 80 answers

Step 1
From the given information,
Consider, X be the random variable which follows the binomial distribution that is, Xb(n=200,p=0.3)
Thus,
Step 2
The sample size is large enough therefore using the central limit theorem and np=200×0.3=60>5 as a result normal approximation to binomial will be used here.
Now, the required probability can be computed as:
Using the continuity factor:
P(X=80)=P(800.5<X<80+0.5)
=P(79.5<X<80.5)
=P(79.5200×0.3200×0.3×0.7<Xnpnp(1p)<80.5200×0.3200×0.3×0.7)
=P(3.0089<Z<3.1632)
=0.000531
Using standard normal table.
Now , will compute the probability using the binomial formula:
P(X=80)=(20080)×(0.3)80×(0.7)20080
=0.000628
Hence, it could be concluded that while using normal approximation to binomial probability is lesser than using binomial formula that is, the difference between both method is 0.0006280.000531=0.000097

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