The quality-control inspector of a production plant will reject a batch of syrin

permaneceerc

permaneceerc

Answered question

2021-09-15

The quality-control inspector of a production plant will reject a batch of syringes if two or more defective syringes are found in a random sample of eight syringes taken from the batch. Suppose the batch contains 1% defective syringes.
Find ? (in terms of the number of syringes).
What is the expected number of defective syringes the inspector will find?
What is the probability that the batch will be accepted?
Find ? (in terms of the number of syringes)

Answer & Explanation

Jaylen Fountain

Jaylen Fountain

Skilled2021-09-16Added 169 answers

Step 1
Let us consider ;
X be the number of syringes being defective as a binomial random variable.
We are given that in the batch ,there can be assumed to be 1% defective syringes.
that is; n=8 (for 8 syringes in our sample) ,
Probability of syringes being defective (p)=0.01
Probability of syringes being not defective (q)=1p=10.01=0.99
Step 2
Calculation:
1] We know that ;
The formula for Expectation in binomial distribution is;
μ=np
=8×0.01
=0.08 syringes
Therefore ;
The inspector will find Expected number of defective is equal to 0.08 syringes
2] We have to find binomial probability for that we will use the binomial probability distribution is given by;
P(X=x)=nCxpx(1p)nx,x=0.1,2,3,.,8
Therefore;
P(x<2)=P(X=0)+P(X=1)
=8C0p0(1p)80+8C1p1(1p)81
=8C0(0.01)0(10.01)80+8C1(0.01)1(10.01)81
=0.9227+8×0.01×0.9321
=0.9227+0.0746
=0.9973
Therefore ;
Probability that the batch will be accepted is equal to 0.9973

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