1.The probability of Christine getting a new job or going on vacation

korporasidn

korporasidn

Answered question

2021-11-12

1.The probability of Christine getting a new job or going on vacation (or both) is 0.85. If the probability of Christine going on vacation is 0.10 and the probability of Christine getting a new job is 0.75, are the events Christine gets a new job and Christine goes on vacation mutually exclusive?
2. The probability that Isabelle will go trick-or-treating is 0.4. The probability that she will go trick-or-treating or watch a scary movie is 0.65. The probability of Isabelle going trick-or-treating and watching a scary movie is 0.20.
A. What is the probability that Isabelle will not watch a scary movie?
B. What is the probability that Isabelle will watch a scary movie but does not go trick-or-treating?

Answer & Explanation

Nicole Keller

Nicole Keller

Beginner2021-11-13Added 14 answers

Step 1
1.Given that
The probability of Christine getting a new job =0.75
the probability of Christine going on vacation =0.10
The probability that getting a new job or going on vacation =0.85
Are the events mutually exclusive
2.
The probability that Isabelle will go trick-or-treating =0.4
The probability that she will trick or treating and watching a scary movie =0.20
The probability that she will trick and treating and watching a scary movie =0.65
A. Find The probability that she will not watch a scary movie
B. Find the probability that she will watch a scary movie but not go trick or treating
Step 2
1.
Let A be the event that Christine getting a new job
Let B be the event that Christine going on a vacation
From the given probabilities
P(A)=0.75
P(B)=0.10
P(AB)=0.85
Events A and B are mutually exclusive
Because the occurrence of event A will not affect the Occurrence of B
From the formula, if P(AB)=P(A)+P(B) A and B can be mutually exclusive events
here 0.75+0.10=0.85
Step 3
2.
Let A be an event that Isabelle will go on trick or treat
Let B be an event that Isabelle will go on watching a scary movie
From the given probabilities
P(A)=0.4
P(AB)=0.65
P(AB)=0.20
a) The probability that she will not watch a scary movie
P(B)=1P(B)
P(B) can be calculated from the relation
P(AB)=P(A)+P(B)P(AB)
P(B)=P(AB)P(A)+P(AB)
=0.650.4+0.20
=0.45
P(B)=10.45
=0.55
b) The probability that she will watch a scary movie but not go trick or treat
P(AB)=P(B)P(AB)
=0.450.20
=0.25

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