The probability of Jay passing the 1st test is 0.6. While the probabil

mronjo7n

mronjo7n

Answered question

2021-11-16

The probability of Jay passing the 1st test is 0.6. While the probability of him passing both of the tests is 0.4. What is the probability of Jay passing the 2nd test given that he has passed the first test?

Answer & Explanation

Momp1989

Momp1989

Beginner2021-11-17Added 21 answers

Step 1
Given: The probability of Jay passing the 1st test is 0.6. while the probability of him passing both of the tests is 0.4.
This problem is an example of conditional probability which is the probability of an event occurring such that another event has already occurred.
It is represented by:
P(AB)=P(AB)P(B), where P(AB) is the Probability of A such that B has already occurred.
Let event A be Jay passing the 2nd test and let event B be Jay passing the 1st test.
The probability of Jay passing the 1st test is 0.6 which implies P(B)=0.6
The probability of Jay passing both the tests is 0.4 which implies P(AB)=0.4
Step 2
So the Probability of Jay passing the 2nd test given that he has passed the first test is:
P(AB)=P(AB)P(B)
P(AB)=0.40.6
P(AB)=0.66
Thus, the Probability of Jay passing the 2nd test given that he has passed the first test is 0.66.

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