Roll a fair die 10 times. What is the probability to get “six” twice?

pavitorj6

pavitorj6

Answered question

2021-11-19

Roll a fair die 10 times. What is the probability to get “six” twice? And, What is the probability to get “six” at least twice?

Answer & Explanation

Louise Eldridge

Louise Eldridge

Beginner2021-11-20Added 17 answers

Step 1
The required solution is as follows.
(i) In any throw of a die, the probability of getting 1 is 16. Then the probability of getting any number other than 1
is 116=56.
Hence, the probability of getting 6 two times in 10 throw
=10C2×(16)2×(56)8
=0.2929
Step 2
ii) Similarly, probability of getting at least 2 two times in 10 throws of a die = 1- Probability of getting 0 or 1 times
Probability of getting number 6, zero, or one time,
=10C0×(16)0×(56)10+10C1×(16)1×(56)9
Therefore, the probability of getting at least 2 two times in 10 throws of a die is = 1- Probability of getting 0 or 1 times
The probability of getting at least 2 two times in 10 throws of a die =10.4730=0.527
Therefore, the required probability is 0.527

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