diferira7c

2021-12-27

The chance of an IRS audit for a tax return reporting more than 25,000 in income is about 2% per year

a. give the distribution of X.$X\sim B$ (__,__)

b. how many audits are expected in a 20 year period?

c. find the probability that a person is not audited at all.

d. find the probability that a person is all the dead more than twice.

a. give the distribution of X.

b. how many audits are expected in a 20 year period?

c. find the probability that a person is not audited at all.

d. find the probability that a person is all the dead more than twice.

usaho4w

Beginner2021-12-28Added 39 answers

Step 1

Since you have posted a question with multiple sub-parts, we will solve first three sub- parts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved

(a) Determine the distribution of X.

The distribution of X is determined below as follows:

Let X denotes the number of audits a person with the income more than 25,000 which follows binomial distribution with the probability of success 0.02 and the number of years selected is 20.

That is,$n=20,p=0.02,q=0.98(=1-0.02)$ .

Therefore,

$X\sim B(20,0.02)$

Step 2

(b) Obtain the expected number of audits in a 20 year period.

The expected number of audits in a 20 year period is obtained below as follows:

The required value is,

$E\left(x\right)=np$

$=20\times 0.02$

$=0.40$

The expected number of audits in a 20 year period is 0.40.

Step 3

(c) Obtain the probability that a person is not audited at all.

The probability that a person is not audited at all is obtained below as follows:

The required probability

Use Excel to obtain the probability value for x equals 0.

Follow the instruction to obtain the P-value:

1. Open EXCEL

2.Go to Formula bar.

3. In formula bar enter the function as“=BINOMDIST”

4. Enter the number of success as 0.

5. Enter the Trails as 20

6. Enter the probability as 0.02

7. Enter the cumulative as False.

8. Click enter

EXCEL output:

From the Excel output, the P-value is 0.6676

The probability that a person is not audited at all is 0.6676.

Since you have posted a question with multiple sub-parts, we will solve first three sub- parts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved

(a) Determine the distribution of X.

The distribution of X is determined below as follows:

Let X denotes the number of audits a person with the income more than 25,000 which follows binomial distribution with the probability of success 0.02 and the number of years selected is 20.

That is,

Therefore,

Step 2

(b) Obtain the expected number of audits in a 20 year period.

The expected number of audits in a 20 year period is obtained below as follows:

The required value is,

The expected number of audits in a 20 year period is 0.40.

Step 3

(c) Obtain the probability that a person is not audited at all.

The probability that a person is not audited at all is obtained below as follows:

The required probability

Use Excel to obtain the probability value for x equals 0.

Follow the instruction to obtain the P-value:

1. Open EXCEL

2.Go to Formula bar.

3. In formula bar enter the function as“=BINOMDIST”

4. Enter the number of success as 0.

5. Enter the Trails as 20

6. Enter the probability as 0.02

7. Enter the cumulative as False.

8. Click enter

EXCEL output:

From the Excel output, the P-value is 0.6676

The probability that a person is not audited at all is 0.6676.

braodagxj

Beginner2021-12-29Added 38 answers

Step 1

a) In words, dene the Random Variable X.

Solution:

X = number of audits a person with income over $25,000 per annum has in a 20 year period.

b) List the values that X may take on.

Solution:

c) Give the distribution of X.

Solution:

or we could use the mean value calculated below and approximate with the Poisson distribution

d) How many audits are expected in a 20 year period?

Solution:

karton

Expert2022-01-04Added 613 answers

Step 1

Given:

X=the number of audits a person with income over $25,000 per annum has in a 20 year period and the values of X are

Here X follows the Binomial distribution with the parameters n=20 and p=0.02

a) The number of audits are expected in a 20-year period is

Mean,

b) Standard deviation,

The standard deviation is 0.6261

c) The probability function of Binomial Distribution is given by

So probability of being audited troice is

d)

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an LG Smartphone survey). If 8 adult smartphone users are randomly selected, find the probability that exactly 6 of them use their smartphones in meetings or classes?

Write formula for the sequence of -4, 0, 8, 20, 36, 56, 80, where the order of f(x) is 0, 1, 2, 3, 4, 5, 6 respectively

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of the experiment.n=20,

p=0.7,

x=19

P(19)=

In binomial probability distribution, the dependents of standard deviations must includes.

a) all of above.

b) probability of q.

c) probability of p.

d) trials.The probability that a man will be alive in 25 years is 3/5, and the probability that his wifewill be alive in 25 years is 2/3

Determine the probability that both will be aliveHow many different ways can you make change for a quarter??

(Different arrangements of the same coins are not counted separately.)One hundred people line up to board an airplane that can accommodate 100 passengers. Each has a boarding pass with assigned seat. However, the first passenger to board has misplaced his boarding pass and is assigned a seat at random. After that, each person takes the assigned seat. What is the probability that the last person to board gets his assigned seat unoccupied?

A) 1

B) 0.33

C) 0.6

D) 0.5The value of $(243{)}^{-\frac{2}{5}}$ is _______.

A)9

B)$\frac{1}{9}$

C)$\frac{1}{3}$

D)01 octopus has 8 legs. How many legs does 3 octopuses have?

A) 16

B 24

C) 32

D) 14From a pack of 52 cards, two cards are drawn in succession one by one without replacement. The probability that both are aces is...

A pack of cards contains $4$ aces, $4$ kings, $4$ queens and $4$ jacks. Two cards are drawn at random. The probability that at least one of these is an ace is A$\frac{9}{20}$ B$\frac{3}{16}$ C$\frac{1}{6}$ D$\frac{1}{9}$

You spin a spinner that has 8 equal-sized sections numbered 1 to 8. Find the theoretical probability of landing on the given section(s) of the spinner. (i) section 1 (ii) odd-numbered section (iii) a section whose number is a power of 2. [4 MARKS]

If A and B are two independent events such that $P(A)>0.5,P(B)>0.5,P(A\cap \overline{B})=\frac{3}{25}P(\overline{A}\cap B)=\frac{8}{25}$, then the value of $P(A\cap B)$ is

A) $\frac{12}{25}$

B) $\frac{14}{25}$

C) $\frac{18}{25}$

D) $\frac{24}{25}$The unit of plane angle is radian, hence its dimensions are

A) $[{M}^{0}{L}^{0}{T}^{0}]$

B) $[{M}^{1}{L}^{-1}{T}^{0}]$

C) $[{M}^{0}{L}^{1}{T}^{-1}]$

D) $[{M}^{1}{L}^{0}{T}^{-1}]$Clinical trial tests a method designed to increase the probability of conceiving a girl. In the study, 340 babies were born, and 289 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born?