raja.ir02
2022-01-31
10. What is the probability of these events whenwe randomly select a permutation of the 26 lowercase letters of the English alphabet?
a) The first 13 letters of the permutation are in alphabetical order.
b) a is the first letter of the permutation and z is the last letter.
c) a and z are next to each other in the permutation.
d) a and b are not next to each other in the permutation.
e) a and z are separated by at least 23 letters in the permutation.
f ) z precedes both a and b in the permutation.
alenahelenash
Expert2022-03-09Added 556 answers
a) The first 13 letters of the premutatuion are in alphabetical order.
probability
d) a and b are not next to each other in the permutation.
We need to se;ect 26 out of 26 letters and we need to determine the number of permutations.
We could find that
The probability is the number of favorable outcomes divided by the number of possible outcomes.
P (a and b not next to each other)
e) The number of possible permutation of 26 letters if
So number of ways to place a and z is 4 ways.
Now, when any one of a and z is placed at second place in 2 ways then another one of a and z can be places in 1 ways at 26th place.
So, number of ways to place a and z is 2 ways.
So, total number of ways to place a and z is
The remaining 24 places can be arranged in
So, total number of ways to select a permutation of the 26 letters of the English alphabet in such a way that a and z are separate by at least 23 letters in permutation is
So, the probability is
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