A bin contains 71 light bulbs, of which 9 are

assumingsun

assumingsun

Answered question

2022-02-11

A bin contains 71 light bulbs, of which 9 are defective. If 6 light bulbs are randomly selected from the bin without replacement of the selected bulbs, what is the probability that all of the selected bulbs are good?

Answer & Explanation

Kristin Ferrell

Kristin Ferrell

Beginner2022-02-12Added 9 answers

Nine of the 71 light bulbs in the trash bin are broken. Thus, 62 of them are effective. We have chosen 6 bulbs, and we want them to be all excellent.So, the good bulbs must come from the 62 bulbs and this is possible in (62c6) ways. The total possibilities are (71c6) since we select 6 bulbs from the 71 bulbs available for selection. Finally, the probability is obtained as the ratio mentioned. 
This Problem is to be solved using Binomial Distribution. 
If a ball is taken randomly from the bin the ball being defective is q=971
The ball not being defective is p=1991=6271 
The desired event is not being defective. 
Let x be the number of desired event. 
We expect x=6 
Px=6=6C6(px)(qnx) 
Px=6=6C6(6271)6(971)66 
Px=6=6C6(6271)6(971)0 
Px=6=(1)(6271)6(1) 
Px=6=(1)(6271)6(1) 
Px=6=(1)(0.44)(1) 
Px=6=0.44

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