P(E)=0.24\ \text{and}\ P(F)=0.3. What is P(E \cup F)?

lahierba9qj

lahierba9qj

Answered question

2022-02-12

P(E)=0.24 and P(F)=0.3. What is P(EF)?

Answer & Explanation

taibidzhl

taibidzhl

Beginner2022-02-13Added 17 answers

The probability of P or F occurring is 0.468
Explanation:
The formula is:
P(AB)=P(A)+P(B)P(AB)
Basically you take the probability of E+F minus the probability of both events happening.
In terms of (EF):
P(EF)=P(E)+P(F)P(EF)
Plug in the values:
P(EF)=P(0.24)+P(0.3)P(0.24×0.3)
P(EF)=0.24+0.3(0.072)
P(EF)=0.540.072
P(EF)=0.468

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