In Texas holdem, one is dealt a Decent Hand (Any pocket pair or any two broadway cards) ∼

Kozankaht2

Kozankaht2

Answered question

2022-05-28

In Texas holdem, one is dealt a Decent Hand (Any pocket pair or any two broadway cards) 15 percent of the time. If there are three people left in the hand, I can use the probability addition rule to say at least one of those three people left will show up with a Decent Hand 45 percent of the time, correct? What about when there are 10 people left? Does someone show up with a Decent Hand 150% of the time?
Edit: Why does the addition rule not suited for this case?

Answer & Explanation

Liberty Gates

Liberty Gates

Beginner2022-05-29Added 11 answers

The addition rule of probability states that for two events, the measure of their onion is equal to the sum of the measures of the events minus the measure of their intersection:
P ( A B ) = P ( A ) + P ( B ) P ( A B )
When these events are mutually exclusive, then P ( A B ) = 0, so :
P ( A B ) = P ( A ) + P ( B )
But only when this is so. The events of each of several people receive decent hands from the same deal of a deck are not mutually exclusive. More than one such person may be dealt a decent hand at the same time.
Anahi Jensen

Anahi Jensen

Beginner2022-05-30Added 4 answers

No, you cannot. The quality of their hand influences the likelihood of them staying in the hand and even if we ignore this, "the probability addition rule" means something very different. If you deal a hand to three people, the chance that at least one of them has a "decent hand" (ignoring that this is not independent) is 1 0.85 3 .
edit: Previously I wrote incorrectly 0.15 instead of 0.85

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