This is one of our probability exercise: We have an urn with m green balls and n yellow balls.

Leonel Contreras

Leonel Contreras

Answered question

2022-06-23

This is one of our probability exercise:

We have an urn with m green balls and n yellow balls. Two balls are drawn at random. What is the probability that the two balls have the same color?
(a) Assume that the balls are sampled without replacement.
(b) Assume that the balls are sampled with replacement.
(c) When is the answer to part (a) larger than the answer to part (b)? Justify your answer. Can you give an intuitive explanation for what the calculation tells you?

For (a), I think there are only two possible outcomes of this experiment, which are either two green balls or two yellow balls. Since they are independent on each other, so we can use the addition rule. Since it is without replacement, so we can directly use combinations.
P ( same color ) = ( m 1 ) × ( m 1 1 ) + ( n 1 ) × ( n 1 1 ) ( m + n 2 )
The difference between replacement and no replacement is how the candidate pool changes after each action. With replacement, we don't need to modify the number of candidates anymore.
P ( same color ) = ( m 1 ) × ( m 1 ) + ( n 1 ) × ( n 1 ) ( m + n ) 2
However, I have no clues how to solve (c). I tried to use algebra to simplify my answer for (a) and (b), but it doesn't help.
Any hints or suggestions would be appreciated!

Answer & Explanation

Rebekah Zimmerman

Rebekah Zimmerman

Beginner2022-06-24Added 32 answers

In answer to part c), if you write, in the form of an inequality in m and n, "answer to part(a) > answer to part(b)", this inequality reduces to the statement
m n < 0
which is clearly never true.
Intuitively this means that by replacing the first ball you increase the chances of picking the same colour again because there are more of that colour available to be chosen.

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