There are 7 red and 5 yellow fish in an aquarium. Three fish are randomly caught in a net. Find the

doturitip9

doturitip9

Answered question

2022-07-14

There are 7 red and 5 yellow fish in an aquarium. Three fish are randomly caught in a net. Find the probability that the fish were:
a) All red
b) Not all of the same color.

I have solved this question using the method for dependent events as follows:
a) 7 12 6 11 5 10 = 210 1320
b) 1 ( 7 12 6 11 5 10 + 5 12 4 11 3 10 ) = 1170 1320
Is it possible to use combinations to solve this question? If yes, how?

Answer & Explanation

kawiarkahh

kawiarkahh

Beginner2022-07-15Added 15 answers

(a)
( 7 3 ) ( 12 3 )
You can show that this equals what you did.
( 7 3 ) ( 12 3 ) = 7 ! 3 ! 4 ! 12 ! 3 ! 9 ! = 7 6 5 3 2 1 3 2 1 12 11 10 = 7 12 6 11 5 10
(b)
1 ( 7 3 ) ( 12 3 ) ( 5 3 ) ( 12 3 )
Wronsonia8g

Wronsonia8g

Beginner2022-07-16Added 1 answers

a)
( 7 3 ) ( 5 0 ) ( 12 3 )
b)
1 ( 7 3 ) ( 5 0 ) ( 12 3 ) ( 7 0 ) ( 5 3 ) ( 12 3 )

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school probability

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?