What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses? Aa Bb Cc Dd * Aa Bb Cc Dd

Raelynn Nolan

Raelynn Nolan

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2022-08-18

What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses?
Aa Bb Cc Dd × Aa Bb Cc Dd

Answer & Explanation

Payten Daniels

Payten Daniels

Beginner2022-08-19Added 11 answers

If both parents have the genotype Aa Bb Cc Dd, their phenotype is determined by the dominant alleles for these four traits. If we observe on trait, we have 3 times bigger possibility for a dominant (AA, Aa, and Aa) than recessive phenotype (aa). Since we observe four different traits, the probability for an ofspring to look like their parents is 
34343434=0,32.
The number of possible phenotypes is 2 for each of the 4 traits (for example Aa and aa for the first trait), which makes it 16 (2 2 2 * 2).

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