Problem 1. 10 identical bulbs, of which 6 will be yellow. He randomly plants 6 of the bulbs. Prob that exactly 4 are yellow.

Leroy Gray

Leroy Gray

Answered question

2022-09-11

Problem 1. 10 identical bulbs, of which 6 will be yellow. He randomly plants 6 of the bulbs. Prob that exactly 4 are yellow.
Isn't this binomial prob?
I did as follows 6 C 4 ( .6 ) 4 ( .4 ) 2 to get 0.311. Answer is 3 7 .
Problem 2. Bag of bulbs of which 40% produce red tulips. Plant 15 of them. Prob that 6 will be red? I did similar: 15 C 6 ( .4 ) 6 ( .6 ) 9 to get 20.7% which I think is correct.
Are these the same type of problems, and why isn't Problem 1 working?

Answer & Explanation

darkflamexivcr

darkflamexivcr

Beginner2022-09-12Added 14 answers

Step 1
The first question does not follow binomial distribution as each draw is not identical.
Step 2
The first part can be computed as follows:
( 6 4 ) ( 4 2 ) ( 10 6 ) = 3 7
where the numerator is the number of ways to have exactly 4 yellows and the denominator is the total possible way of outcome when we choose 6 bulbs.

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