Negative Binomial: Y ~ NB (r,p) for r = number of success and p is the probability of each success p(k)=p(Y=k)=((k-1),(r-1)) p^r(1-p)^{k-r}, r >= k

tsuyakas1

tsuyakas1

Answered question

2022-09-13

Negative Binomial: Y N B ( r , p ) for r = number of success and p is the probability of each success
p ( k ) = p ( Y = k ) = ( r 1 k 1 ) p r ( 1 p ) k r , r k
then
P r ( l Y k ) = P r ( Y k ) P ( Y l 1 ) = P r ( N k r ) P r ( N l 1 r )
where N k is the number of successes in the first k trials and N l 1 the number of successes in the first l-1 trials.
I'm not understanding how theses equate to each other, why is it greater than equal to?
P r ( Y k ) P ( Y l 1 ) = P r ( N k r ) P r ( N l 1 r )

Answer & Explanation

Vicente Macias

Vicente Macias

Beginner2022-09-14Added 15 answers

Step 1
Y counts the number of trials until r successes. Nk counts the successes in the first k trials.
Y k is the event of r successes occurring in no more than k trials.
N k r is the event of r or more successes in the first k trials.
Step 2
These are the same event, that the r-th success does not occur after the k-th trial.
So their probabilities had better be equal.
P ( Y k ) P ( Y l 1 ) = P ( N k r ) P ( N l 1 r )

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