Complete the following probability table. (Round Prior Probabilty and Posterior Probability answer to 2 decimal places and Joint Probability answer to 4 decimal places)

ubumanzi18

ubumanzi18

Answered question

2022-09-14

Complete the following probability table. (Round Prior Probabilty and Posterior Probability answer to 2 decimal places and Joint Probability answer to 4 decimal places)
Prior Probability Conditional Probability Join Probability Posterior Probability P ( B ) 0.52 P ( A | B ) 0.13 P ( A B ) P ( B | A ) P ( B C ) P ( A | B C ) 0.47 P ( A S C ) P ( B C | A ) Total P ( A ) Total

Answer & Explanation

incibracy5x

incibracy5x

Beginner2022-09-15Added 21 answers

Step 1
Given that:
P ( B ) = 0.52 ,   P ( A | B ) = 0.13 ,   hence   P ( A B ) = 0.52 × 0.13 = 0.0676 P ( B C ) = 0.48 ,   P ( A | B C ) = 0.47 ,   hence   P ( A B C ) = 0.48 × 0.47 = 0.2256 Total = 1 Now P ( A ) = P ( A B ) + P ( A B C ) = 0.0676 + 0.2256 = 0.2932 Hence , P ( B | A ) = P ( B A ) P ( A ) = 0.0676 0.2932 = 0.23 P ( B C | A ) = P ( B C A ) P ( A ) = 0.2256 0.2932 = 0.77 Total = 1 I hope this solves your doubt. Feel free to comment if you still have any query or need something else. I'll help asap.

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