A company has 500 employees, and 60% of them have children. Suppose that we randomly select 4 of these employees. What is the probability that exactly 3 of the 4 employees selected have children? We know that 300 of these employees have children. I tried to figure it out, how to work with the binomial equation by the given's

cuuhorre76

cuuhorre76

Answered question

2022-09-12

A company has 500 employees, and 60% of them have children.
Suppose that we randomly select 4 of these employees.
What is the probability that exactly 3 of the 4 employees selected have children?
We know that 300 of these employees have children.
I tried to figure it out, how to work with the binomial equation by the given's

Answer & Explanation

Julianna Crawford

Julianna Crawford

Beginner2022-09-13Added 8 answers

Step 1
The probability that the first person picked has kids is 300 500 . Conditional on that, the probability that the second person picked has kids is 299 499 . Conditional on all that, the probability the third person has kids is 298 498 . Conditional on all that, the probability the fourth person doesn't have kids is 200 497 . So multiply these together and scale by 4 (since the person without kids could have been any of the four).
Step 2
An alternative perspective: the number of quadruples where exactly three have kids is ( 300 3 ) ( 200 1 ) . There are ( 500 4 ) quadruples in total, so divide the two to get the probability.

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