It's known that birth months are uniformly distributed. A class is divided into 10 groups of 5 students. A group that all five members were born in different months is our interest. What is the probability that there is one such group of interest among 10 groups?

mafalexpicsak

mafalexpicsak

Answered question

2022-10-16

It's known that birth months are uniformly distributed. A class is divided into 10 groups of 5 students. A group that all five members were born in different months is our interest. What is the probability that there is one such group of interest among 10 groups?

Answer & Explanation

occuffick24

occuffick24

Beginner2022-10-17Added 13 answers

Step 1
P(5 randomly chosen ppl are all in different months ) = 11 12 × 10 12 × 9 12 × 8 12 = 55 144 .
Step 2
Define Y to be the number of interesting groups out of 10 groups.
Y B ( 10 , 55 144 ) .
P ( Y = 1 ) =
P ( Y 1 ) =
depending on what you want.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school probability

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?