Laila Murphy

2022-11-20

What kind of technique is to be adopted if I have to find an equation or model for say, $D$ depends on $C$, $C$ changes for a set of $B$, which changes for different $A$.

hitturn35

Beginner2022-11-21Added 20 answers

Let money invested at 3% =x

at $4\mathrm{\%}=50000-x$

Time for both = 1 year

$SI=\frac{P\times T\times R}{100}\phantom{\rule{0ex}{0ex}}(SI{)}_{3\mathrm{\%}}-(SI{)}_{4\mathrm{\%}}=30\phantom{\rule{0ex}{0ex}}\therefore \frac{x\times 1\times 3}{100}-\frac{(5000-x)\times 1\times 4}{100}=30\phantom{\rule{0ex}{0ex}}3x-4(50000-x)=3000\phantom{\rule{0ex}{0ex}}3x-200000+4x=3000\phantom{\rule{0ex}{0ex}}7x=203000\phantom{\rule{0ex}{0ex}}x=29000$

Money at 3% = $29000

4%=$21000

at $4\mathrm{\%}=50000-x$

Time for both = 1 year

$SI=\frac{P\times T\times R}{100}\phantom{\rule{0ex}{0ex}}(SI{)}_{3\mathrm{\%}}-(SI{)}_{4\mathrm{\%}}=30\phantom{\rule{0ex}{0ex}}\therefore \frac{x\times 1\times 3}{100}-\frac{(5000-x)\times 1\times 4}{100}=30\phantom{\rule{0ex}{0ex}}3x-4(50000-x)=3000\phantom{\rule{0ex}{0ex}}3x-200000+4x=3000\phantom{\rule{0ex}{0ex}}7x=203000\phantom{\rule{0ex}{0ex}}x=29000$

Money at 3% = $29000

4%=$21000

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