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2022-05-26
Point charges q= 50 μC and 92=-25C are
placed 1.0 m apart. What is the force on a third charge 93= 20 μC placed midway between 1 and 4₂?
karton
Expert2022-07-07Added 613 answers
Though the question doesn't state where the charges are in relation to the observer, for the sake of definiteness let's say is on the left and is on the right. By the Principle of Superposition of Forces, we know that we can consider each force on individually and then just add them together (keeping in mind direction).
From Coulomb's law, we know that the magnitude of the force on due to is given by
In this case, m since is halfway between the two charges. So then
Now let's think about the direction of the force. is a positive charge and so is . So those two particles will want to repel each other. Since is on the left, will feel a force in the positive direction.
Now let's consider the force due to charge . Again, we use Coulomb's law to get the magnitude.
And this time the charges have opposite sign and so attract each other. Since is on the right of , the force due to it will also point in the positive direction.
So the total force is just the sum of the two since they point in the same direction. That is, the force has a magnitude of newtons and points in the direction of from (remember we said it was to the right, but the question didn't so all we can say is it's in the direction).
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