What is the angle of refraction (relative to the boundary normal) of a diamond in contact with water according to Snell's law? The indices of refraction for water and diamond are respectively 1.33 and 2.42.

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What is the angle of refraction (relative to the boundary normal) of a diamond in contact with water according to Snell&#039;s law? The indices of refraction for water and diamond are respectively 1.33 and 2.42.

Freddy Doyle · Accepted Answer

The equation for this situation is      n          w      a      t      e      r        sin  ⁡      θ          w      a      t      e      r        =      n          d      i      a      m      o      n      d        sin  ⁡      θ          d      i      a      m      o      n      d      Since we know       θ          w      a      t      e      r       , and       n          w      a      t      e      r        ≈  1.33 and       n          d      i      a      m      o      n      d        ≈  2.42, solve for       θ          d      i      a      m      o      n      d      .      θ          d      i      a      m      o      n      d        =  arcsin  ⁡  (            n              w        a        t        e        r                    n              d        i        a        m        o        n        d              sin  ⁡      θ          w      a      t      e      r        )Remember that angles of refraction are with respect to the normal.

What is the angle of refraction (relative to the boundary

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