Nannie Mack

2021-09-20

Work each problem. Find a value of c so that y=x^2−10x+c has exactly one x-intercept.

Nathalie Redfern

Skilled2021-09-21Added 99 answers

If a quadratic function has a single x intercept it must have its minimum y=0. Vertex occurs when $x=-\frac{b}{2}a=\frac{10}{2}=5$

Solve for c whem x=5, y=0

$0={5}^{2}-10\left(5\right)+c$

0=25-50+c

0=-25+c

25=c

Solve for c whem x=5, y=0

0=25-50+c

0=-25+c

25=c

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