Mus. Spring Analysis I Suppose that x\left(t\right)=4\cos4t-3\sin4t

xcl3411

xcl3411

Answered question

2021-11-16

Mus. Spring Analysis I Suppose that x(t)=4cos4t3sin4t+5tsin4t I is the solution of a mass-spring system mi +bi+kx=F(t),x(O)=xo,.i(O)=fo Assume that the homogeneous solution is not identically
(a) Determine the pan of the solution associaaed with the homogeneous DE.
(b) Calculate the amplitude of the oscillation of the homogeneous solution.
(c) Determine the amplitude of the panicular solution.
(d) Which part of the solution will be unchanged if the conditions are changed?
(e) If the mass is 1 kg, what is the spring constant?
(f) Describe the motion of the mass according to the solution.

Answer & Explanation

Wasither1957

Wasither1957

Beginner2021-11-17Added 17 answers

Step 1
Given data:
*The solution of the mass spring system is x(t)=4cos4t3sin4t+5tsin4t.
*The spring mass system is mx+bx+kx=F(t), with x(0)=x0, x(0)=v(0)
a)
The solution of the homogeneous differential equation is in the form,
c1cosω0t+c2sinω0t
Thus, the solution is,
x(t)=4cos4t3sin4t.
b)
The amplitude of the oscillation of the homogeneous solution is,
A=c12+c22
42+(3)2
=5
Thus, the amplitude is 5 units.
c)
The amplitude of the particular solution is time varying and the amplitude is,
A=5t.
Step 2
4)
The constant of the homogenous solution c1 and c2, are dependent on the initial condition thus the homogeneous part of the solution changes by changing the initial condition but the particular solution is unchangeable.
e)
The angular velocity of the system is given by:
km
4=k1kg
k=16
Thus, the spring constant is 16 when the mass is 1 kg.
f)
Here, ω0=ωt=4.
which means the angular frequency of the system is equal to the angular frequency of the forced motion in forced oscillation thus the system continues in pure resonance and the system oscillate in increasing amplitude.

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