William Boggs
2022-01-17
usumbiix
Beginner2022-01-17Added 33 answers
Step 1
Introduction:
The spinner has 12 equal-sized sectors, so when it is spun once, there is an equal chance that it will land on any of the 12 sectors. As a result, there is a 1/12 chance of landing on any of the sectors.
Step 2
Solution:
Since there are 5 out of 12 red sectors, the probability that the spinner lands on a red sector is 5/12.
Since there are 4 out of 12 blue sectors, the probability that the spinner lands on a blue sector is 4/12.
Since there are 2 out of 12 yellow sectors, the probability that the spinner lands on a yellow sector is 2/12.
Since there are 1 out of 12 green sectors, the probability that the spinner lands on a green sector is 1/12.
Next, the event that the spinner lands on a yellow sector, and the event that the spinner lands on a green sector are mutually exclusive, so that the intersection of these two events is a null set, with probability 0.
Hence, the probability of the event that the spinner lands on a yellow or green sector is the sum of the probability of the event that the spinner lands on a yellow sector, and the probability of the event that the spinner lands on a green sector.
The probability of the event that the spinner lands on a yellow or green sector is:
2/12+1/12
=3/12
=1/4
=0.25
Therefore, the probability that the spinner lands on yellow or green is 1/4 or 0.25.
Navreaiw
Beginner2022-01-18Added 34 answers
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