Range of multivariable function z=e^(x+y) arctan(y/x)

Ignacio Riggs

Ignacio Riggs

Answered question

2022-10-19

Range of multivariable function z = e x + y arctan ( y x )

Answer & Explanation

Kash Osborn

Kash Osborn

Beginner2022-10-20Added 18 answers

Well we need that
π 2 < y x < π 2
Because of the arctangent, the exponential accepts any number.
If you multiply with 2 x you get
x π < 2 y < x π
This can be changed into a single inequality by making all the x and y absolute values, you can check that the following is equvalent to the above by doing the cases with the absolute value.
2 | y | < π | x |
The range is then simple the set of all pairs ( x , y ) such that the inequality is true, which is written as
{ ( x , y ) R 2 : 2 | y | < π | x | }

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