When the spacecraft's fusion efficiency is 0.01%, the spacecraft's fusion fuel is 1t, and the total mass of the spacecraft is 1.2t, the friend bet the final speed of the spacecraft is 80% of the speed of light. The state of the fuel at nuclear fusion is assumed to be D + T and 0.01% of the maximum energy of the fusion of the fuel, although the fusion method has not yet been firmly determined. I am curious about the answer of the final speed of this space ship.

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When the spacecraft&#039;s fusion efficiency is 0.01%, the spacecraft&#039;s fusion fuel is 1t, and the total mass of the spacecraft is 1.2t, the friend bet the final speed of the spacecraft is 80% of the speed of light. The state of the fuel at nuclear fusion is assumed to be D + T and 0.01% of the maximum energy of the fusion of the fuel, although the fusion method has not yet been firmly determined. I am curious about the answer of the final speed of this space ship.

Superina0xb4i · Accepted Answer

Restating the numbers to make sure they&#039;re right:- After burning the fuel, the remaining mass is 200kg- Of the 1000kg of fuel burned, 0.1kg (0.01%) is turned into kinetic energy of the remaining mass.If so, here&#039;s how you calculate the result:  γ  =  E      /    m  =  200.1      /    200  =  1.0005From   γ  =  1      /        1    −          v      2              /              c      2      , we get       v    2        /        c    2    =  1  −  1      /        γ    2  Plugging in the numbers:  v  =  c      1    −    1          /              1.0005      2        =  0.032  c or about 9,500 km/sec.Fast, but not 0.8c. That would require   γ  =  1.67, which in turn requires a much higher efficiency and more fuel.

When the spacecraft's fusion efficiency is 0.01%, the spacecraft's fusion fuel is 1t, and the total

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