How many numbers lie between 11 and 1111 which when divided by 9 leave a remainder of 6 and when divide by 21 leave a remainder of 12? ___

compatidakjjn

compatidakjjn

Answered question

2023-02-25

How many numbers lie between 11 and 1111 which when divided by 9 leave a remainder of 6 and when divide by 21 leave a remainder of 12? ___

Answer & Explanation

davz198888za

davz198888za

Beginner2023-02-26Added 9 answers

If the potential number is N, it can be written as
N = 9k + 6
and N = 21l + 12
9 k + 6 = 21 l + 12 9 k 21 l = 6
or 3(3k - 7l) = 6
or 3k = 7l + 2 or k = 7 l + 2 3
Therefore, set l to its lowest possible value such that k's value is an integer, or the numerator, in other words. (i. e., 7l+ 2) will be divisible by 3.
Thus at I =1, we get k = 3 (an integer). So the least possible number N = 9 × 3 + 6 = 21 × 1 + 12 = 33 .
The higher numbers can now be achieved by multiplying the LCM of 9 and 21 by 33. i.e., The general form of the number is 63m + 33. So the other number in the given range including 33 are 96, 159, 222, 285, 348, ..., 1104. Hence there are total 18 numbers which satisfy the given condition.

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