The concentrated sulfuric acid we use in the laboratory is 98% H2SO4 by mass. Calculate the molality and molarity of the acid solution. The density of the solution is 1.83 gmL answers are 5×10−2 m, 18.3M

Question

gwibdaithq · Accepted Answer

Mass percent of H2SO4 solution=98%  98%(m/m) H2SO4 solution means 98 g of H2SO4 solute is present per 100 g of solution.  Mass of H2SO4 solute =98 g  Mass of water =(100-98)g  =2g×1 kg1000 g  =0.002 kg  Mass of H2SO4 solute =98 g  Molar mass of H2SO4 solute =98.09 g/mol  No of moles of H2SO4 solute =98g×1mol98.09g  =0.999 mol  Molality=No of moles of  H2SO4  solutemass of  H2O  solvent  =0.999 mol0.002 kg  =5.0×102 mol/kg  =5.0×102 m  Therefore, the molality of the 98% H2SO4 solution is 5.0×102 m  Mass of H2SO4 solution=100g  Density of H2SO4 solution=1.83gmL  Volume of solution =100 g H2SO4×1 mL1.83 g H2SO4×1 L1000 mL  =0.999 mol  Molality=No of moles of  H2SO4  soluteVolume of solution  =0.999 mol0.0546 L  =18.3 mol/L  =18.3 M  Therefore, the molarity of H2SO4 solution is 18.3 M

The concentrated sulfuric acid we use in the laboratory is 98% H_2SO_4 by mass. Calculate the molality and molarity of the acid solution. The density of the solution is 1.83 \frac{g}{mL} answers are 5\times10^{-2} m, 18.3M

Answered question

Answer & Explanation

New Questions in Other