Lead has a specific heat of 0.030 cal/gC. In an insulated container, 300 grams of lead shot heated to 100°C and 100 grams of water heated to 70°C are combined. The mixture's final temperature is:A) 100C&nbsp;b) 85.5C&nbsp;c)79.5C&nbsp;d) 74.5C&nbsp;e)72.5C

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Lead has a specific heat of 0.030 cal/gC. In an insulated container, 300 grams of lead shot heated to 100°C and 100 grams of water heated to 70°C are combined. The mixture&#039;s final temperature is:A) 100C&amp;nbsp;b) 85.5C&amp;nbsp;c)79.5C&amp;nbsp;d) 74.5C&amp;nbsp;e)72.5C

unett · Accepted Answer

According to the principle of calirometry or heat balance, heat lost equals heat gained.m1c1(T1−T)=m2c2(T−T2)&amp;nbsp;m1=300grams,c1=0.030calg.C,T1=100C&amp;nbsp;m2=100grams,c2=1,T2=70C&amp;nbsp;You will receive the response 86.81C, which is (b)

Jeffrey Jordon · Accepted Answer

300⋅0.03(100−T)=100⋅1⋅(T−70)  0.09(100−T)=T−70  9−0.09T=T−70  ⇒1.09T=79  T=791.09≈72.47∘C  E)

The specific heat of lead is 0.030 cal/g.C. 300 grams of leadshot at 100C is mixed with 100 grams of water at 70C in an insulated container. The final temperature of the mixture is: A) 100C b) 85.5C c)79.5C d) 74.5C e)72.5C

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