Bevan Mcdonald

2020-12-05

A 5.00kg sack of flour is lifted vertically at a constant speed of 3.50m/s through a height of 15.0m. a) How great a force is required? b) How much work is done on the sack by the lifting force? What becomes of this work?

Sadie Eaton

Skilled2020-12-06Added 104 answers

a) F - mg = 0

F = mg = (5)(9.81) = 49.05N

b)$W=F\cdot d=\left(49.05\right)\left(15\right)=735.75\text{}J$

c) This work becomes potential energy

F = mg = (5)(9.81) = 49.05N

b)

c) This work becomes potential energy

22+64

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