A black body at 7500K consists of an opening of diameter0.0500mm, looking into an oven. Find the number of photonsper second escaping the hole and hav

OlmekinjP

OlmekinjP

Answered question

2021-02-03

A black body at 7500K consists of an opening of diameter 0.0500mm, looking into an oven. Find the number of photonsper second escaping the hole and having wavelengths between 500nm and 501nm. Hint: use equation 40.6 for I(λ,T); then find Power=I(λ,T)(λ1λ2)  Area; then set nhcλ=Power×1  second and solve for n, thenumber of photons emitted in 1second. Let λ=12(λ1+λ2)

Answer & Explanation

Pohanginah

Pohanginah

Skilled2021-02-04Added 96 answers

A black body at 7500K consists of an opening ofdiameter 0.0500mm, looking into an oven. Find the number ofphotons per second escaping the hole and having wavelengths between 500nm and 501nm for this we apply the stefen's law
powerarea=?T4
power=energy(E)time(t)
energy=nhc?
hence nhc?tA=?T4
the number of photons per second escaping thehole and having wavelengths between 500nm and 501nm. is

nt=?T4hc?A?=5.67×108Wm2K4
T=7500K
h=6.62×1034
Jsc=3×10
8m/s?=(500+5012)nm
A=?r2
r=0.025×103m  plug the values and calculate for theanswer

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