boitshupoO
2020-11-30
Bentley Leach
Skilled2020-12-01Added 109 answers
The electric flux through each face of the cube is given by
where E is the magnitude of the electricfeild at the face, A is the area of the face, and Ø is theangle between the electric field and the outward nornal of theface. We can use this expression to calculate the electric flux
through each of the six faces of the cube. a) on the bottom face of the cube, the outward normal pointsparallel to the - axis, in the opposite direction to the electricfield, and
Therefore,
(in your case instead ofthe use your m i used the number from the book.
On the top face of the cube, the outward normal pointsparallel to the + axis, and the flux . The electric fluxis, therefore,
On each of the other four faces, the outward normals areperpendicular to the direction of the electric field, so
so for each of the four sides faces,
b) The total flux through the cube is:
you should end up with a final answer of 0N•m²/C . Because each side is 0, and the bottom isa negative and the top is a postive of each amounts of flux. sothey cancel.
22+64
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