An olympic long jumper leaves the ground at an angle of23degress and travels through the air for a horizontal distance of8.7m before landing what is the take off speed? Could you kindlyassist me?
arenceabigns
Answered question
2020-10-20
Answer & Explanation
Cristiano Sears
Skilled2020-10-21Added 96 answers
where R is the range (the horizontal distance traveled),v0 is the initial velocity, ? is the takeoff angle,and g is the acceleration due to gravity (9.81 m/s)
Rearranging this equation to solve for v0 youget
Inserting the given info, v0 = 10.9 m/s
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