A particlewith a charge of 5.5×10–8C charge is fixed at theorigin. A particle with a charge of –2.3×10–8C charge ismoved from x = 3.5 cm onthe x axis to y = 3.5 cm on the y axis. The change in the potentialenergy of the two-charge system is: Chapter 24, Test bank Question 4 3.2×10–4J –3.2×10–4J 9.3×10–3J –9.3×10–3J

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A particlewith a charge of 5.5×10–8C charge is fixed at theorigin. A particle with a charge of –2.3×10–8C charge ismoved from x = 3.5 cm onthe x axis to y = 3.5 cm on the y axis. The change in the potentialenergy of the two-charge system is:    Chapter 24, Test bank Question 4    3.2×10–4J    –3.2×10–4J    9.3×10–3J    –9.3×10–3J

hajavaF · Accepted Answer

Because potential energy is a scalar and depends on distance (which is constant), the product of charges (which is constant), and potential energy, there is no change in potential energy.U=(14??0)(5.5×10–8C)–2.3×10–8C3.5×10−2&amp;nbsp;J ISCONSTANT ON X-AXIS AND Y-AXIS

A particlewith a charge of 5.5\times 10–8C charge is fixed at theorigin. A particle with a charge of –2.3\times 10–8C charge ismoved from x = 3.5 cm o

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