A 58-kg skier is going down a slope oriented 35 degree abovethe horizontal. The area of each ski in contact with the snowis 0.13 m2. Determine the pressure that each skiexerts on the snow.

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lamusesamuset · Accepted Answer

P=F/S  F=mgcos⁡35  S=0.13 m2  so Pressure can be calculated

Jeffrey Jordon · Accepted Answer

To solve this problem we will use a free body diagram that allows us to determine the Normal Force.  In general, the normal force would be equivalent to  N=mgcos⁡θ  Since the skier is standing on two skis, his weight will be divide by two  N‘=mgcos⁡θ2  Pressure is given as the force applied in a given area, that is  P=FA  Replacing F with N&#039;  P=N‘A  P=mgcos⁡θ2A  Our values are given as,  m=58 kg  g=9.8m/s2  θ=35∘  A=0.13m2  Replacing we have that  P=(5.8)(9.8)cos⁡(35)20.13  P=776.01 Pa  Therefore the pressure exerted by each ski on the snow is 776.01 Pa

A 58-kg skier is going down a slope oriented 35 degree abovethe horizontal. The area of each ski in contact with the snowis 0.13 m2. Determine the pressure that each skiexerts on the snow.

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