A solution was prepared by dissolving 1210 mg of K_{3}Fe(CN)_{6} (329.2 g/mol) in sufficient waterto give 775 mL. Calculate: a) the molar analytical c
boitshupoO
Answered question
2020-12-12
a) the molar analytical concentration of
b) the molar concentration of
c) the molar concentration of
d) the weight/volume percentage of
e) the number of millimoles of
f) ppm
g) pK for the solution
h)
Answer & Explanation
krolaniaN
Skilled2020-12-13Added 86 answers
I am using ur calculated value
Molarity of
Moles = molarity * V(L)
Mass of
= 0.7788g
ppm = mass of solute / mass of solution
= 0.7788g / 775 g
= 1005 ppm
= 1.005 mg/ L
Hope its clear to U!
for the molarity of
Jeffrey Jordon
Expert2021-10-08Added 2605 answers
(a):
Given values:
Mass of
Molar mass of
Volume of solution = 775 mL
Plugging values in equation 1:
b)
The equation for the dissociation of
1 mole of
Molar concentration of
c)
Molar concentration of
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