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Elleanor Mckenzie

Answered question

2021-03-25

Ea for a certain biological reaction is 50 kJ/mol, by what factor ( how many times) will the rate of this reaction increase when body temperature increases from 37 C (normal ) to 40 C (fewer)?

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Ayesha Gomez

Skilled2021-03-27Added 104 answers

Arrhenius equation: k=Aexp(-Ea/RT)
where k is rate constant, A is pre-exponential factor, Ea is activation energy, R is molar gas constant and T is temperature in K.

\ln (\frac{k_{2}}{k_{1}}) = (\frac{- E a}{R}) \times (\frac{1}{T_{2}} - \frac{1}{T_{1}})

E_{a} = 50 K \frac{j}{m} o l = 50000 \frac{J}{m} o l

T_{1} = 37 d e g C = 310 K

T_{2} = 40 d e g C = 313 K

\ln (\frac{k_{2}}{k_{1}}) = (\frac{- 500000}{8.314} \times (\frac{1}{313} - \frac{1}{310}) = 0.18594

\frac{k_{2}}{k_{1}} = \exp (0.18594) = 1.2

Since rate is proportional to rate constant

\frac{R a t e (2)}{R a t e (1)} = \frac{k_{2}}{k_{1}} = 1.2

Thus the rate increases by a factor of 1.2 times

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