The best laboratory vacuum has a pressure of about&nbsp;1.00⋅10−18&nbsp;atm, or&nbsp;1.01⋅10−13Pa. In such a vacuum at 293 K, how many gas molecules are present per cubic centimeter?

The gases law is PV = nRT, you solve for n = number of moles: n=PV/RT where P=1.01×10−13Pa,V=1×10−6m3, R = 8.31 and T = 293 K, then remember that 1 molehas 6.022×1023 molecules

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2021-04-21

The best laboratory vacuum has a pressure of about $1.00 \cdot 10^{- 18}$ atm, or $1.01 \cdot 10^{- 13} P a$ . In such a vacuum at 293 K, how many gas molecules are present per cubic centimeter?

Answer & Explanation

Macsen Nixon

Skilled2021-04-23Added 117 answers

The gases law is PV = nRT, you solve for n = number of moles:
n=PV/RT where

P = 1.01 \times 10^{- 13} P a, V = 1 \times 10^{- 6} m^{3}

, R = 8.31 and T = 293 K, then remember that 1 molehas

6.022 \times 10^{23}

molecules

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