Clifland

2021-10-03

twelve years ago, a man was three times as old as his daughter. Nice years from now the man will be twice as old as his son. Four years form now, the sum of the ages of son and daughter will equal the age of the man. How old is each now?ars ago, a man

Arnold Odonnell

Skilled2021-10-04Added 109 answers

x=age of man

y=age of daughter

z=age of son

x-12=3y

x+9=2z

y+4+z+4=x

x=12+3y

12+3y=y+z+8

4+2y=z

12+3y+9=

21+3y=2(4+2y)

21+3y=8+4y

13=y

z=4+2y=4+26=30

x=12+3(13)=12+39=51

man is 51, daughter is 13, son is 30

y=age of daughter

z=age of son

x-12=3y

x+9=2z

y+4+z+4=x

x=12+3y

12+3y=y+z+8

4+2y=z

12+3y+9=

21+3y=2(4+2y)

21+3y=8+4y

13=y

z=4+2y=4+26=30

x=12+3(13)=12+39=51

man is 51, daughter is 13, son is 30

22+64

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