In open-heart surgery, a much smaller amount of energy will defibrillate the hea

rompentskj

rompentskj

Answered question

2021-11-20

In open-heart surgery, a much smaller amount of energy will defibrillate the heart. (a) What voltage is applied to the 8.00μF capcitor of a heart defibrilator of a heart defibrilator that 40.0J of energy? b( Find the amount of the stored charge

Answer & Explanation

Witionsion

Witionsion

Beginner2021-11-21Added 19 answers

Identify the unknown:
The voltage in the capacitor
List the Knowns:
Capacitance of the capacitor: C=8μF=8×106 F
Energy stored in the capacitor: UC=40J
Set up the problem
Energy stores in a capcitor:
UC=12V2C
V=2UCC
Solve the problem:
V=2×408×106=3162V
b. Identify the unknown:
The stored charge
Set up the problem:
Energy stored in a capacitor:
UC=12QV
Q=2UCV
Solve the problem:
Q=2×403162=0.0253 C
Result: a. 3162 kV
b. 25.3 mC

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