A lens is 16.0 cm away from an object. The lens forms an image 36.0cm to the right of the lens.&nbsp;a)What is the focal length of the lens?&nbsp;b) Is the lens converging or diverging?

(a) f=ss′s+s′=(16.0 cm)(36.0 cm)16.0 cm+36.0 cm=11.1 cm. f&gt;0 and the lens is converging.(b) m=−s′s=−36.0 cm16.0 cm=−2.25.|y′|=|m|y=(2.25)(8.00 mm)=18.0 mm. m&lt;0, so the image is inverted.

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Holly Guerrero

Answered question

2021-12-12

A lens is 16.0 cm away from an object. The lens forms an image 36.0cm to the right of the lens.
a)What is the focal length of the lens?
b) Is the lens converging or diverging?

Answer & Explanation

puhnut1m

Beginner2021-12-13Added 33 answers

(a)

f = \frac{s s^{'}}{s + s^{'}} = \frac{(16.0 c m) (36.0 c m)}{16.0 c m + 36.0 c m} = 11.1 c m

. f>0 and the lens is converging.
(b)

m = - \frac{s^{'}}{s} = - \frac{36.0 c m}{16.0 c m} = - 2.25 . | y^{'} | = | m | y = (2.25) (8.00 m m) = 18.0 m m

. m<0, so the image is inverted.

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