Margie Marx

2021-12-14

A 6kg bucket of water is being pulled straight up by a string at a constant speed. The tension on the string was F = ma

$F=(6kg\times 9.8\frac{m}{s}2)$ , $F=58.8N$ Now its asking At a certain point the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude $3\frac{m}{{s}^{2}}$ . What is the tension in the rope now? The correct answer was "about 78N" then Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude $3\frac{m}{{s}^{2}}$ .What is the tension in the rope?

Jonathan Burroughs

Beginner2021-12-15Added 37 answers

Firstly, $\sum {F}_{y}=T-mg=m{a}_{y}=0$

As${a}_{y}=0$ , so $\Rightarrow T-mg=0$

$T=mg=6.0\times 9.8=58.8$

Now, use the same formula to find the tension in the rope.

Do the acceleration, when the bucket has an upward acceleration, it means that it has a positive value$a}_{y}=+3\frac{m}{{s}^{2}$

When it has a downward acceleration, it means that it has a negative value of$a}_{y}=-3\frac{m}{{s}^{2}$

Now,

$\sum {F}_{y}=T-mg=m{a}_{y}=+3.0\times 6$

$T-mg=18$

$T=18+mg=18+(6.0\times 9.8)=76.8N$

Now, you should apply the same thing into the downward acceleration

$\sum {F}_{y}=T-mg=m{a}_{y}=-3.0\times 6$

$T-mg=-18$

$T=18+mg=-18+(6.0\times 9.8)=40.8N$

$T=40.8N$

As

Now, use the same formula to find the tension in the rope.

Do the acceleration, when the bucket has an upward acceleration, it means that it has a positive value

When it has a downward acceleration, it means that it has a negative value of

Now,

Now, you should apply the same thing into the downward acceleration

xleb123

Skilled2023-06-14Added 181 answers

Jazz Frenia

Skilled2023-06-14Added 106 answers

fudzisako

Skilled2023-06-14Added 105 answers

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