David Troyer

Answered question

2021-12-15

The average distance between Earth and the Sun is $1.5×{10}^{11}m$.
(a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second. (b) What is this speed in miles per hour?

Answer & Explanation

zesponderyd

Beginner2021-12-16Added 41 answers

We know the average distance $\left[{d}_{g}\right]$ from the Earth to the Sun $=1.5×{10}^{11}m$
The travel distance ${d}_{1}$ is given:
${d}_{1}=2\pi ×{d}_{g}=2\pi ×1.5×{10}^{11}=9.424×{10}^{11}m$
And ${v}_{1}$ is given by:
${v}_{1}=\frac{{d}_{1}}{t}=\frac{9.424×{10}^{11}m}{1year}=\frac{9.424×{10}^{11}m}{365.25day×24×3600s}\approx 3×{10}^{4}\frac{m}{s}$
The speed of Earth on average $=29862.85\frac{m}{s}$
Speed is given by:
${v}_{2}=29862.85\frac{m}{s}×\frac{3600}{1609.34}\approx 6.7×{10}^{4}m\frac{i}{h}$
Therefore, (a) ${v}_{1}=3×{10}^{4}\frac{m}{s}$, (b) ${v}_{2}=6.7×{10}^{4}m\frac{i}{h}$

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?