David Troyer

2021-12-15

The average distance between Earth and the Sun is $1.5\times {10}^{11}m$ .

(a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second. (b) What is this speed in miles per hour?

(a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second. (b) What is this speed in miles per hour?

zesponderyd

Beginner2021-12-16Added 41 answers

We know the average distance $\left[{d}_{g}\right]$ from the Earth to the Sun $=1.5\times {10}^{11}m$

The travel distance $d}_{1$ is given:

${d}_{1}=2\pi \times {d}_{g}=2\pi \times 1.5\times {10}^{11}=9.424\times {10}^{11}m$

And $v}_{1$ is given by:

$v}_{1}=\frac{{d}_{1}}{t}=\frac{9.424\times {10}^{11}m}{1year}=\frac{9.424\times {10}^{11}m}{365.25day\times 24\times 3600s}\approx 3\times {10}^{4}\frac{m}{s$

The speed of Earth on average $=29862.85\frac{m}{s}$

Speed is given by:

$v}_{2}=29862.85\frac{m}{s}\times \frac{3600}{1609.34}\approx 6.7\times {10}^{4}m\frac{i}{h$

Therefore, (a) $v}_{1}=3\times {10}^{4}\frac{m}{s$, (b) $v}_{2}=6.7\times {10}^{4}m\frac{i}{h$

22+64

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