A long, straight solenoid with a cross-sectional area of 8.00 cm2 is wound with 90 turns of wire per centimeter, and the windings carry a current of 0.350 A. A second winding of 12 turns encircles the solenoid at its center. The current in the solenoid is turned off such that the magnetic field of the solenoid becomes zero in 0.0400 s. What is the average induced emf in the second winding?

Question

MoxboasteBots5h · Accepted Answer

Expression for magnetic field  B=μ0ni  Where,  μ0=4π×10−7 nA−2  Given values:  n=90 per cm to per m=9000  i=0.350 A  Placing all known values in equation  B=3π×10−7×90×102×0.350 A  =3.9×10−3 T  Expression for average induced emf-  ϵ=NA△B△t  Where,  N=12  A=8 cm2=8×10−4 m2  △B=3.9×10−4 m2  △t=0.04 s  Placing known values give us-  ϵ=12×(8×10−4 m2)3.9×10−3 T0.04 s  =9.3×10−4 V

A long, straight solenoid with a cross-sectional area of 8.00 cm2 is w

Answered question

Answer & Explanation

New Questions in Other