When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm. a. What is the fleas

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When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.   a. What is the fleas

SlabydouluS62 · Accepted Answer

Step 1 Given values: viy=0ms vfy=1ms yi=0m yf=0.5⋅10−3m g=9.81ms2 a) In this case, we have to determine value of acceleration. The best way to find that is using the kinematic equation: vf2=vi2+2a(△y). Plug in values in above equation and solve for acceleratiion: vfy2=viy2+2ay(yf−yi) (1ms)2=(0ms)+2ay(0.5⋅10−3m−0m) (1m2s2=2ay(0.5⋅10−3m) ay=(1m2s2)2(0.5⋅10−3m) ay=1000ms2 Step 2 b) Use the kinematic equation to find value of time: vfy=viy+ayt Plug in values in above equation and solve for time: 1ms=0ms+(1000ms2)t t=1ms−0ms(1000ms2) t=1ms(1000ms2) t=10−3s c) It is moving straight up, so it&#039;s final speed is equal to zero when it reaches the highest point is using the kinematic equation: vf2=vi2+2a(△y) If we plug in values in above equation, we get: vfy2=viy2+2ay(yf−yi)

Donald Cheek · Accepted Answer

Step 1 Part A. Following equation will be used: v2−u2=2as where v is the final velocity , u is the initial velocity, a is the acceleration and s is the distance traveled Given values are as follows: v=1ms,u=0ms,s=0.5×10−3m Therefore, v2−u2=2as (1)2−(0)2=2×a×5×10−3 a=100ms2 Step 2 Part B. Here time is need to be calculated by following equation: v=u+at 1=0+100× t=0.01s Part C. If the flea jumps straight up then the acceleration due to gravity will be taken into account and following equation will be used. v2−u2=2gs Given values are as follows: v=0ms,u=1ms,g=−9.8ms2 Therefore, v2−u2=2gs (0)2−(1)2=−2×9.8×s s=0.051m

Nick Camelot · Accepted Answer

We have:a=v2−u22swhere:a is the average acceleration,v is the final velocity,u is the initial velocity, ands is the displacement.Given that the initial velocity u is 0 m/s (since the flea starts from rest), the final velocity v is 1.0 m/s, and the displacement s is 0.50 mm (or 0.50 × 10−3 m), we can substitute these values into the equation:a=(1.0m/s)2−(0m/s)22×(0.50×10−3m)Simplifying further:a=1.0m/s21.0×10−3ma=1.0×103m/s2Therefore, the flea&#039;s average acceleration is 1.0×103m/s2.

When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distanc

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