Anne Wacker

2022-01-03

An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s, what length open-open pipe is needed? What length open-closed pipe would suffice?

aquariump9

Beginner2022-01-04Added 40 answers

The formula for a standing wave's frequency in an open-ended tube is

$f}_{1}=\frac{v}{2L$

$L=\frac{v}{2{f}_{1}}$

$L=\frac{343}{2\times 27.5}$

$L=6.236\text{}m$

The formula for a standing wave's dor frequency in an open-close tube is

$f}_{1}=\frac{v}{4L$

$L=\frac{v}{4{f}_{1}}$

$L=\frac{343}{4\times 27.5}$

$L=3.118\text{}m$

22+64

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